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If xyz + xy + yz + xz + x + y + z = 104, where x, y , z are natural numbers, then find x + y + z. a) 12 b) 14 c)10 d)20
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I think 12.
How?
Hmm idk, I used Brute Force! I tried 6,3,3 and 6,4,2. {6,4,2} is the integer solution.
Bhaiya, please say step by step. Please.
I am trying to get an algebraic solution.
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