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Mathematics 21 Online
OpenStudy (anonymous):

If xyz + xy + yz + xz + x + y + z = 104, where x, y , z are natural numbers, then find x + y + z. a) 12 b) 14 c)10 d)20

OpenStudy (anonymous):

I think 12.

OpenStudy (anonymous):

How?

OpenStudy (anonymous):

Hmm idk, I used Brute Force! I tried 6,3,3 and 6,4,2. {6,4,2} is the integer solution.

OpenStudy (anonymous):

Bhaiya, please say step by step. Please.

OpenStudy (anonymous):

I am trying to get an algebraic solution.

OpenStudy (anonymous):

Okay

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