Question

Solve [3/(x-1)] - [(2x+10)/(x^2+2x-3)] = 1/3
help please , thanks!

Answer 1

\[ [3/(x-1)] - [(2x+10)/(x^2+2x-3)] = 1/3\]

Answer 2

1/x+3=1/3
x=0

Answer 3

(3/x-1)*(x+3)....(3x+9-2x-10)/(x-1)(x+3)=1/x+3=1/3...x=0

Answer 4

\[(3(x+3)-(2x+10))/{(x-1)(x+3)}=1/3\]
\[(x-1)/{(x-1)(x+3)}=1/3\]
1/(x+3)=1/3
x=0

Answer 5

thank you so much, i understand now :)