Question

What is the 32nd term of the arithmetic sequence where a1 = –31 and a9 = –119?

Answer 1

a9 = a1 + d(8)

solve for d with the given information to determine the 32nd term

Answer 2

a32 = a1+d(31)

Answer 3

whats the anwser?

Answer 4

what answer id you get when you did that?

Answer 5

i got -339

Answer 6

let me chk if thats good :)

Answer 7

-119 =-31 + d(8)

(-119+31)/8 = d

a32 = -31 + ((-119+31)/8)(31) = -372

Answer 8

oh i see thank you !!

Answer 9

your welcome :)

Answer 10

is it -339

Answer 11

No I believe it is -372 like amistre had said...not sure though