Question

how would i solve this....
1-3y/5 =2

Answer 1

is this:\[\text{a) }1-\frac{3y}{5}=2\]or,\[\text{b) }\frac{1-3y}{5}=2\]

Answer 2

b

Answer 3

ok, first step would be to multiply both sides by 5 to get rid of the denominator on the left hand side

Answer 4

ok

Answer 5

is the answer y =- 1/3

Answer 6

so you woud get:\[5*\frac{1-3y}{5}=5*2\]\[\cancel{5}*\frac{1-3y}{\cancel{5}}=5*2\]\[1-3y=10\]

Answer 7

oh okay i found out what i did wrong
i multiply 5 with the other numbers on top too..
thank you

Answer 8

yw