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If \[\int\limits_{a}^{b}\] f(x) dx = a +2b then \[\int\limits_{a}^{b}\] (f(x) +5) dx = what?
\[\int_a^b 5 dx =5\times(b-a)\]
(a+2b+5b)-( a+2b+5a) = 5(b-a)
integral of a constant is the constant times the length of the path|dw:1327546356263:dw|
so i guess your final answer is \[a+2b+5(b-a)\] which you can probably clean up with some algebra
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