Question

x^2+x-20 / 5x^2+23x-10

Answer 1

To do this equation, you must first factor both numerator and denominator,
I have already done such as [(x+5)(x-4)]/[(x+5)(5x-2)]

knowing this, we can cancel out x+5 from both numerator and denominator, however we must note that there is a hole at that point.
After this the Verticle asymptote is x =/= 0.4