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OpenStudy (anonymous):
x^2+x-20 / 5x^2+23x-10
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OpenStudy (anonymous):
To do this equation, you must first factor both numerator and denominator, I have already done such as [(x+5)(x-4)]/[(x+5)(5x-2)] knowing this, we can cancel out x+5 from both numerator and denominator, however we must note that there is a hole at that point. After this the Verticle asymptote is x =/= 0.4
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