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PLEASE HELP!!!!!!!! what is log base 3 six square root 243 (where 6 is inside the "v" of the square root"
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\[\log _{3} \sqrt[6]{243}\]
\[\log_{3}\sqrt[6]{243} \] like this?
yes.
alright lemme see what i can do
okay, can u help me with a few others as well? i am really not understanding logs :(
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no problem. You know the rule of logs? Where logANS / logBASE = expo?
?
so in this case log [\sqrt[6]{243}\] / log3 = 5/6
i don't really get it..can you draw it out?
|dw:1327550139579:dw|
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