http://www.google.com/imgres?hl=en&biw=1366&bih=623&gbv=2&tbm=isch&tbnid=QQzWW46sAvkaAM:&imgrefurl=http://pballew.blogspot.com/2011/01/nedial-triangle.html&docid=gM6N094cJ9z13M&imgurl=http://3.bp.blogspot.com/_PQZIFRiZz38/TSneI1aw0qI/AAAAAAAACcI/khHHmlP7B-c/s400/nedialtri.jpg&w=327&h=262&ei=pd0gT4z1DMKqiAKuqK3UBw&zoom=1&iact=hc&vpx=1072&vpy=287&dur=126&hovh=201&hovw=251&tx=168&ty=72&sig=111848135009093379071&page=1&tbnh=131&tbnw=145&start=0&ndsp=20&ved=1t:429,r:12,s:0

Question

http://www.google.com/imgres?hl=en&biw=1366&bih=623&gbv=2&tbm=isch&tbnid=QQzWW46sAvkaAM:&imgrefurl=http://pballew.blogspot.com/2011/01/nedial-triangle.html&docid=gM6N094cJ9z13M&imgurl=http://3.bp.blogspot.com/_PQZIFRiZz38/TSneI1aw0qI/AAAAAAAACcI/khHHmlP7B-c/s400/nedialtri.jpg&w=327&h=262&ei=pd0gT4z1DMKqiAKuqK3UBw&zoom=1&iact=hc&vpx=1072&vpy=287&dur=126&hovh=201&hovw=251&tx=168&ty=72&sig=111848135009093379071&page=1&tbnh=131&tbnw=145&start=0&ndsp=20&ved=1t:429,r:12,s:0 <<<Given: In ΔABC, E, D, and F are midpoints Prove: ΔCED≅ΔDFB≅ΔEAF≅ΔFDE

dumbcow · Answer

the midsegment thm says that any midsegment is half the length of its corresponding side

|dw:1327555040735:dw|
then by using Side-side-side postulate all 4 triangles are congruent