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OpenStudy (anonymous):
Factor completely. xy-2x+4y-8
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OpenStudy (anonymous):
(x+4)(y-2)
OpenStudy (anonymous):
xy-2x+4y-8 =x(y-2)+4(y-2) =(x+4)(y-2)
OpenStudy (anonymous):
xy+2x+4y+8?
OpenStudy (anonymous):
yamaka just answered it... thrice. Factor by grouping.
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