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Mathematics 8 Online
OpenStudy (anonymous):

Solve: |5x + 2| + 7 < 19

hero (hero):

:D

OpenStudy (anonymous):

:D is the final answer.

OpenStudy (anonymous):

A. x < 2 and x > -14/5 B. x < 2 and x < -14/5 C. x > 2 and x > 14/5 I'm not sure how to get the second half...

OpenStudy (hoblos):

|5x + 2| < 12 -12< 5x+2 < 12 -14< 5x < 10 -14/5 < x < 2

hero (hero):

|5x + 2| + 7 < 19 |5x + 2| < 19 - 7 |5x + 2| < 12 -12 < 5x + 2 < 12 -14 < 5x < 10 -14/5 < x < 2

OpenStudy (hoblos):

A

hero (hero):

I don't like the way they present the possible solutions

hero (hero):

In general, if |x - a| < b, then -b < x - a < b

hero (hero):

You read it like this: If the absolute value of x minus a is less than b, then x minus a is between negative and positive b

hero (hero):

And then you continue solving for x

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