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Solve: |5x + 2| + 7 < 19
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:D
:D is the final answer.
A. x < 2 and x > -14/5 B. x < 2 and x < -14/5 C. x > 2 and x > 14/5 I'm not sure how to get the second half...
|5x + 2| < 12 -12< 5x+2 < 12 -14< 5x < 10 -14/5 < x < 2
|5x + 2| + 7 < 19 |5x + 2| < 19 - 7 |5x + 2| < 12 -12 < 5x + 2 < 12 -14 < 5x < 10 -14/5 < x < 2
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A
I don't like the way they present the possible solutions
In general, if |x - a| < b, then -b < x - a < b
You read it like this: If the absolute value of x minus a is less than b, then x minus a is between negative and positive b
And then you continue solving for x
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