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OpenStudy (anonymous):

The filament of a light bulb has a temperature of 2580 degrees C and radiates 600 Watts of power at room temperature of 20 degrees C. the emissivity of filament is 0.36. Whats the surface area of the filament? I have it narrowed down to either 0.44 cm^2 or 0.144 cm^2. I can't seem to solve correctly. Please help.

OpenStudy (anonymous):

Let's treat it as a blackbody. \[P = \epsilon \sigma A_s T^4\]

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