Question

y varies inversely as three times x. When x = 3, y = 4. What is the value of x when y = 2? can someone help me solve?

Answer 1

Diya! Diya!

Answer 2

y varies inversely as three times x
\[y=k \times \frac{1}{3x}\]
\[4=k \times \frac{1}{3*3}=\frac{k}{9}\]\[4= \frac{k}{9} \ \ or \ \ k= 9*4=36\]\[k=36\]
\[ Now\ for \ y=2\]
\[2= k \times \frac{1}{3x}= \frac{k}{3x}\]\[2= \frac{k}{3x}=\frac{36}{3x}\]\[2*3x=36 \]\[6x=36\]\[x=\frac{36}{6} =6\]\[x=6\]

Answer 3

varies "inversely". Sometimes I post too quickly

Answer 4

This is known as inverse proportion :)

Answer 5

Diya deserves the medal, not me, lol

Answer 6

Thanks (: