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fourth root of 128n to the 8th power
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\[(128n)^2\]
\[^{} \sqrt[4]{128}n ^{8}\] thats the anwser for this question?
um. Well, your wording in the original question is rather ambiguous.
sorry em the question was to simplify \[\sqrt[4]{128}n ^{8}\]
Ahh
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:(
\[2*2^{3/4}*n^8=2\sqrt[4]{8}n^8\]
Or, is the \[n^8\] inside the square root or did you really mean \[\sqrt[4]{128}n^8\]
if it was what would the answer b i left the paper
i think it was inside
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ok. Then the answer is \[n^22\sqrt[4]{8}\]
how many more questions would u be willing to do?
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