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Square root of 48x^3 divided by the square root of 3xy^2
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\[\frac{\sqrt{48x^3}}{\sqrt{3xy^2}}=\frac{4x \sqrt{3x}}{y \sqrt{3x}}=\frac{4x}{y}\]
Rite^
cant i do 48/3=\[\sqrt{16x^{2}}y ^{2}= 4xy\]
\[\frac{48}{3}\neq \frac{\sqrt{48}}{\sqrt{3}}\]
\[16 \neq 4\]
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