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3x^2-11x-20/25-x^2 simplify
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\[\frac{(3x+4)(x-5)}{(5-x)(5-x)}\]
Note that the quotient of opposites is -1. So cancel out x-5 and 5-x and get
\[\frac{-(3x+4)}{(5-x)}\]
so 3x+4/5-x is the answer ?
Did you see the negative sign in front of the quantity 3x+4?
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This is the answer in 2 forms:
\[\frac{-(3x+4)}{(5-x)} = \frac{(3x+4)}{(x-5)}\]
Revised answer:\[\frac{-(3x+4)}{5+x}\]
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