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integral of sec^4 x * cos^2x * tan ^7x dx tired and brain dead someone do it for me plz
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if you want an answer try http://www.wolframalpha.com/input/?i=sec^4+x+*+cos^2x+*+tan+^7x+dx
pellet son thats a convenient cheater box u got there
but you see it is simple answer and that is because \[\sec^4(x)\times \cos^2(x)=\frac{\cos^2(x)}{\cos^4(x)}=\sec^2(x)\]
so really you just have \[\int\tan^7(x)\sec^2(x)dx\] and a simple u -sub gives it in one step
oh wow thats embarrassing
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lol
ok one more
right circular cylinder is inscribed in a cone with height h and base radius r Find the largest possible volume of such a cylinder
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