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How do you solve this inequality? n-5/2<2n-6/3
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is that \[\frac{n-5}{2}<\frac{2n-6}{3}\]
yes
Actually <_
but I doubt it would make a difference
\[(\frac{n-5}{2})\le(\frac{2n-6}{3})\] \[(\frac{n-5}{2})(3)\le(\frac{2n-6}{3})(3)\] \[(\frac{n-5}{2})(2)(3)\le(2n-6)(2)\] \[(n-5)(3)\le(2n-6)(2)\] \[-15\le n-12\] \[ -3\le n\] \[n \ge -3\]
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THANK YOU SO MUCH! can you help me with one more?
Sure :)
i'll post a question with your name and give another medal to you
okay :)
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