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Mathematics 20 Online
OpenStudy (anonymous):

evaluate (a) sin^-1 (1/2) and (b) tan ( arcsin 1/3)

OpenStudy (dumbcow):

ok sinA = 1/2 what is A?

OpenStudy (anonymous):

it is inverse i think

OpenStudy (anonymous):

sin

OpenStudy (dumbcow):

sine of what angle gives you 1/2

OpenStudy (anonymous):

1?

OpenStudy (dumbcow):

think unit circle 0,pi/6, pi/4 ....

OpenStudy (dumbcow):

for part b) you have to write tan in terms of only sine tan = sin/cos = sin/sqrt(1-sin^2) then sin(sin^-1x) = x --> (1/3)/sqrt(1-1/9)

OpenStudy (anonymous):

sorry im kind of a bit slower :(

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