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evaluate (a) sin^-1 (1/2) and (b) tan ( arcsin 1/3)
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ok sinA = 1/2 what is A?
it is inverse i think
sin
sine of what angle gives you 1/2
1?
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think unit circle 0,pi/6, pi/4 ....
for part b) you have to write tan in terms of only sine tan = sin/cos = sin/sqrt(1-sin^2) then sin(sin^-1x) = x --> (1/3)/sqrt(1-1/9)
sorry im kind of a bit slower :(
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