Question

Find the x-, y-, and z-intercepts for the equation.
9x + 3y - 6z = 18

Answer 1

18/n

where n is the coeff of the intercept your looking for gives you that intercept

Answer 2

18/9,0,0

0, 18/3, 0

0,0 18/-6

Answer 3

\[z = -3 + (3 x)/2 + y/2 \]\[9 x+3 y-6 z-18 = 0 \]\[3 (3 x + y - 2 z) = 18 \]

Answer 4

There more comming

Answer 5

\[Reduce[3 x + y = 6 + 2 z, {x, y, z}, \mathbb{Z}s] \]

Answer 6

\[[3 x + y = 6 + 2 z, z] \]your answer Solve