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If there are a probability of 20% to get a red ball and 80% to get a blue ball. What is the probability to get exactly 1 red ball when picking out three balls without putting them back?
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With this information, we must assume that there is an infinite number of balls; therefore, the answer is (3 c 1)(0.20)(0.80)(0.80) = 0.384
Probability of a red 0.20 Probability of a no red 0.80 Then: probability of just one red of tree balls is (0.20)(0.80)(0.80) = (0.80)(0.20)(0.80) = (0.80)(0.80)(0.20) = 0.384
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