Question

divide
x^2+8x+15/4x^2+23x+15 divide x^2+6x+9/4x^2-5x-6

Answer 1

\[\frac{x^2+8x+15}{4x^2+23x+15} \cdot \frac{4x^2-5x-6}{x^2+6x+9}\]
\[\frac{(x+5)(x+3)}{4x^2+20x+3x+15} \cdot \frac{(x-6)(x+1)}{(x+3)(x+3)}\]

Answer 2

now i basically have done this problem for you
i left some factoring for you in the denominator of the first fraction(hint factor by grouping)
after that you will cancel some stuff

Answer 3

i m not getting any where

Answer 4

on the part I left you?

Answer 5

do you know how to factor by grouping?

Answer 6

\[4x^2+20x+3x+15=4x(x+5)+3(x+5)\]
can you do it from here?

Answer 7

just factor 4x(x+5)+3(x+5)

Answer 8

and you will be done with the factoring part
then you can cancel stuff