Question

f(x)with radical sign 0.5x-5;f(20),f(16),f(12),f(14)
f(20)=
find domain of the function

Answer 1

can any one solve this

Answer 2

\[f(x)=\sqrt{.5x-5}\]

Answer 3

Is that the function?

Answer 4

If it is the domain is all the numbers that make .5x-5 positive or 0

Answer 5

\[\frac{1}{2}x-5\ge0\]

Answer 6

\[x \ge10\]

Answer 7

That is the domain.

Answer 8

\[f(20)=\sqrt{.5(20)-5}=\sqrt{5}\]

Answer 9

\[f(16)=\sqrt{.5(16)-5}=\sqrt{8-5}=\sqrt{3}\]

Answer 10

\[f(12)=\sqrt{.5(12)-5}=\sqrt{6-5}=\sqrt{1}=1\]

Answer 11

\[f(14)=\sqrt{.5(14)-5}=\sqrt{7-5}=\sqrt{2}\]

Answer 12

type an integer or decimal rounded to the nearest tenth as needed

Answer 13

f(20)=2.2 is the correct answer

Answer 14

Do you have a calculator?

Answer 15

yes

Answer 16

Then pick it up and type square root 5 and see if you don't get 2.2

Answer 17

yes

Answer 18

Now do the others in the same way.

Answer 19

What is the square root of 3?

Answer 20

1.7

Answer 21

What about the square root of 2?

Answer 22

1.4

Answer 23

So now you have all the answers.

Answer 24

so domain of f(x) is all real numbers x where ?

Answer 25

You know, it would really be nice if, when you ask for help, and someone helps you that you would have the common courtesy to read what they wrote.

Answer 26

1 am with you