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Vector PQ = <-3,1,-2> Vector PR = <1,-1,1> PQ x PR = ????
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is that a cross-product?
PQxPR = <-1, 1, 2>
yes
(b) Find the area of the triangle PQR.
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(a) Find a nonzero vector orthogonal to the plane through the points P, Q, and R. Was the first question... but thats the cross product im sure.
squareroot(6)/2
need the points of p q r to do a)
I used P Q R to find vector PQ and vector PR... to find part a i just needed to find the cross product... can you show me the steps please???
you answer is correct.
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ok cwoool
your****
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