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Mathematics 13 Online
OpenStudy (anonymous):

Vector PQ = <-3,1,-2> Vector PR = <1,-1,1> PQ x PR = ????

OpenStudy (turingtest):

is that a cross-product?

OpenStudy (anonymous):

PQxPR = <-1, 1, 2>

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

http://www.youtube.com/watch?v=qsgK1d-_8ik

OpenStudy (anonymous):

(b) Find the area of the triangle PQR.

OpenStudy (anonymous):

(a) Find a nonzero vector orthogonal to the plane through the points P, Q, and R. Was the first question... but thats the cross product im sure.

OpenStudy (anonymous):

squareroot(6)/2

OpenStudy (anonymous):

need the points of p q r to do a)

OpenStudy (anonymous):

I used P Q R to find vector PQ and vector PR... to find part a i just needed to find the cross product... can you show me the steps please???

OpenStudy (anonymous):

you answer is correct.

OpenStudy (anonymous):

ok cwoool

OpenStudy (anonymous):

your****

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