Question

find dy/dx explicitly as dy/dx=g(x,y) if x^3+y^2+4y=4

Answer 1

\[3x^2\div(-2y-4)=(dy \div dx)\]

Answer 2

we have \(x^3+y^2+4y=4\)
differentiate with respect to x
\( 3x^2+2y dy/dx+4 dy/dx=0\)
\((2y+4)dy/dx=-3x^2\)
\[dy/dx= -3x^2/(2y+4)\]

Answer 3

thax loads for your help