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Integral over adjacent intervals interval from 2 to 9 f(x) dx= 3.8 and interval from 6 to 9 f(x)dx=13 find interval from 2 to 6 f(x)dx ??
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\[\int_{2}^{9}f(x)dx=\int_{2}^{6}f(x)dx+\int_{6}^{9}f(x)dx\]therefor\[\int_{2}^{6}f(x)dx=\int_{2}^{9}f(x)dx-\int_{6}^{9}f(x)dx\]
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