Question

factor the sum of cubes
y^3+64

Answer 1

\[a^3+b^3= (a+b)(a^2-ab+b^2)\]

Answer 2

y^3 + 4^3 = y^3 + 64

(y+4) (y^2 - 4y + 16)

Answer 3

so here we have \[a=y,b=4\]

Answer 4

(y+4) (y^2-4 y+16)