Ask your own question, for FREE!
Mathematics 20 Online
OpenStudy (anonymous):

can someone help me with simplifying radicals?

OpenStudy (anonymous):

Go for it.

OpenStudy (precal):

yes, what do you have?

OpenStudy (anonymous):

Well this worksheet that I have to do has some problems that I have no idea on how to do how would I simplify one that was 6 square root 200

OpenStudy (precal):

\[6\sqrt{200}\] is this the problem?

OpenStudy (anonymous):

yes

OpenStudy (precal):

\[6\sqrt{2*100}\] \[6*10\sqrt{2}\] \[60\sqrt{2}\]

OpenStudy (akshay_budhkar):

\[\sqrt{ 200 }= \sqrt 2 \times \sqrt{100} = 10 \times \sqrt2\]

OpenStudy (anonymous):

I have a few more questions. is that ok?

OpenStudy (precal):

go for it @Akshay Budhkar What happened to your 6?

OpenStudy (anonymous):

they must have lost it :)

OpenStudy (akshay_budhkar):

lol i was gonna write it in the next step but u got the answer before it :)

OpenStudy (precal):

I can only help for a couple of minutes (maybe 10)

OpenStudy (akshay_budhkar):

couple is not equal to 10

OpenStudy (precal):

ok but time is going fast and I have other things to do....

OpenStudy (anonymous):

anyway... how would you do (2 square 6 times 3 square root 2?

OpenStudy (anonymous):

and 16/81 all in a square root

OpenStudy (anonymous):

or 3/ the square root of 2

OpenStudy (anonymous):

and the square root of 6 over 3 square root 2

OpenStudy (anonymous):

square root of 4 over square root 11

OpenStudy (precal):

\[2^2(6*3\sqrt{2})\] is this problem? Use the Equation editor on the lower left side to input your problems

OpenStudy (anonymous):

\[(2\sqrt{6})(3\sqrt{2})\]

OpenStudy (precal):

\[\left( 2\sqrt{11} \right)/11\]\[\sqrt{4}/\sqrt{11}\] \[2/\sqrt{11}\] That is the solution for one of the problems Gotta go!

OpenStudy (anonymous):

thanks:)

OpenStudy (precal):

\[6\sqrt{12}\] \[6\sqrt{4*3}\] \[6*2\sqrt{*3}\] \[12\sqrt{*3}\] ok that is for the one you posted correctly

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!