Question

y=2x²/3x²-16
What is the horizontal asymptote for the above function?

y = _____

Answer 1

2/3, as x approaches infinity, y will approach 2/3

Answer 2

divide top and bottom by x^2 gives 2/3 so thats the horizontal asymptote

Answer 3

horizontal asymptote is when \[x \rightarrow infinity\]

so divide top and bottom by x^2
to get \[y= {2 \over 3+{16 \over x^2} }\]

Answer 4

Assuming, of course, that the 16 is in the denominator.