Question

i am on lecture six and using python 2.7.2 whats wrong with my copied code?
##def sqrtbi(x, z):
## assert x>=0, 'x must be non-negitive, not' + str(x)
## assert z > 0, 'espilon must be positive, not' + str(z)
## low = 0
## high = max(x, 1.0)
## guess = (low + high)/2.0
## ctr = 1
## while abs(guess**2 - x) > z and ctr <= 100:
## #print 'low:', low, 'high:', high, 'guess:', guess
## if guess**2 < x:
## low = guess
## else:
## high = guess
## guess = (low + high)/2.0
## ctr += 1
## assert ctr <= 100, 'Ineration

Answer 1

Please give code that is easy to try ! This code is fully commented, and we have to reformat it. Plus it seems to be incomplete (end missing).
Use a pastebin and try to ease the job of those wanting to help...
And explain what is the problem with the code, according to you.

Answer 2

copy paste to text editor, replace all ## to nothing :P

Answer 3

def sqrtbi(x, z):
assert x>=0, 'x must be non-negitive, not' + str(x)
assert z > 0, 'espilon must be positive, not' + str(z)
low = 0
high = max(x, 1.0)
guess = (low + high)/2.0
ctr = 1
while abs(guess**2 - x) > z and ctr <= 100:
#print 'low:', low, 'high:', high, 'guess:', guess
if guess**2 < x:
low = guess
else:
high = guess
guess = (low + high)/2.0
ctr += 1
assert ctr <= 100, 'Ineration count exceeded'
print 'Bi method. Num. Interactios', ctr, 'Estimation', guess
return guess

Answer 4

Thanks, but we still don't know what is the problem with this code. I tested it and it seems to produce good results.

Answer 5

when i test it, the code spits out obserd awnsers such as sqrtbi(9, 0.0001) = 2.25... instead of 3, how can i count on it to find the square root of any given number?