Question

Calc II problem attached:
Need help!

Answer 1

dv/dt = t+ 2 = v = 0.5*(t^2) +2*t+c v(0)=5 ..placing this = c =5

v = 0.5(t^2) + 2t + 5 = dx/dt
x = (1/6)*(t^3) + t^2 + 5t +c ..
distance =x(10)-x(0) = 1000/6 + 100+500
=4600/6

Answer 2

...+50 not ...+500

Answer 3

yeah .. sorry I was calclulating in mind..