Question

Please factor
n^3 - 3n^2 -168n + 720 = 0

Answer 1

\[n^3 - 3n^2 - 168n + 720 = 0\]

Answer 2

And show me how you did it too.

Answer 3

I used trial and error for find f(12) = 0 then (n -12) is a factor

then use polynomial division

\[(n^3 - 3n^2 - 168n + 720)/(x -12) = (n - 12)(n^2 + 9n - 60)\]

to get the other factor