I need help, when (3x^3 + px^2 + qx +8) is divided by (x^2 - 3x +2) , the remainder is (5x+6). how do we find the values of p and q? thank you :)

Question

myininaya · Answer

i will scan this and post it here
too long to do by latex

myininaya · Answer

i just did long division and now we have a set of linear equations to solve

myininaya · Answer

attachment

campbell_st · Answer

the divisor  x^2 -3x +2 is factorised to (x-2)(x-1)

so you can find P(2) and P(1)

myininaya · Answer

so we have from what I did the following equations:
3p+q=-16             ;                   -2p-10=6
                                                   -2p=16 
                                                      p=-8
now just plug this into our other equation to find q
3(-8)+q=-16
-24+q=-16

anonymous · Answer

thanks for taking the trouble to help me solve this question :) i rly appreciate it!

anonymous · Answer

thank you guys! :)