Question

let f(x) =3x^3 -5x^2+4x-6 and g(x) = -8x^2-7x +12,evaluate (f.g)(1/2)
a.13/8
b.13/6
c.-13/4
d.-13/8

Answer 1

lag dont lag this is 2nd to the last question

Answer 2

im getting error now when it comes to 4x-6 short term memory

Answer 3

13/6 letter b

Answer 4

ops w8 wrong theres 1/2

Answer 5

13/6 sir?

Answer 6

\[27x-10x+4x =13 16x-7=9 then 9-12=-3 -6-3 =3 f.g(13/3) (1/2)=13/6\]

Answer 7

ops wrong 1316x =only 13x then 16x-7

Answer 8

is it b or d

Answer 9

what is your answer sir?

Answer 10

we have to find f.g(1/2)
let's find f(x).g(x)
\[f(x).g(x)=(3x^3-5x^2+4x-6)(-8x^2-7x+12)\]
substitute x=1/2
\[f.g(1/2)=(3/8-5/4+4/2-6)(-8/4-7/2+12)\]
on solving we get f.g(1/2)=-507/16
not matching any option
sorry i'd to go somehere in the middle

Answer 11

*somewhere

Answer 12

it will be (-8x-7x)^2 = 8

Answer 13

-8 or 8

Answer 14

how 'd you get this?

Answer 15

im checking my notebook example of my prof XD its not finalized XD

Answer 16

sqrt of 507 = 13sqrt3

Answer 17

letter D final not sure