Question

suppose tanx =(√2)/4 , cos x = -(2√2)/3
find sinx
cscx
sec x
and cot x

Answer 1

tanx=sinx/cosx so tanx*cosx = sinx
cscx=1/sinx
secx=1/cosx
cot=1/tanx

Answer 2

sinx = -1/3
cscx = -3
\[\sec x = -3/2\sqrt{2}\]
\[\cot x = 4/\sqrt{2}\]