Question

split into partial fractions:
4/(y^3-25y)

Answer 1

-4/(25 y)+2/(25 (y+5))+2/(25 (y-5))

Answer 2

4/(y^3-25y) = A/y + B/y-5 + C/ y+5
4 = A((y-5)(y+5) + By(y+5) + Cy(y-5)
let y = 5
4 = 50B
B = 2/25
let y = -5
4 = 50C
C = 2/25
let y = 0
4 = -25A
A = -4/25

so its

-4 2 2
---------- + ---------- + -------
25y 25(y+5) 25(y-5)

if my algebra is correct

Answer 3

the way to check is to work back and see if you get the original exprersion

Answer 4

- oh laurly got same answer