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Mathematics 19 Online
OpenStudy (anonymous):

cos(sinx^2) help plzz with differentiation

OpenStudy (amistre64):

diff cos, what do you get?

OpenStudy (anonymous):

sin

OpenStudy (amistre64):

-sin but yeah so; -sin(sinx^2) now times that by diff the inside sin

OpenStudy (amistre64):

\[sin(x^2)\]or\[sin^2(x)\] which is that inside part?

OpenStudy (anonymous):

so its going to be -sin times 2

OpenStudy (amistre64):

[f(g(h(x)))]' = f'() * g'() * h'() * ()'

OpenStudy (amistre64):

-sin(sin(x^2)) * cos(x^2) * 2x

OpenStudy (anonymous):

so it wud be -sin times cos times 2

OpenStudy (anonymous):

thnx can u help me with some other questions

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