Base and height of triangle whose height is four more than seven times its base. Whats the base and height? Thanks :)
h = 7a + 4 a = (h-4)/7
whats the seven?
height is four more than 7 times its base so h= 7b+4 where b is base so 7b=h-4 b=(h-4)/7
/7 is what i meant :) but thank you for that information
7 is given in the question :) "seven times its base " :)
How do i get the answers, do i solve both?
i hope this is the final answer
which one is the final answer :) is the answer just how its set up?
\[h= 7b+4 \]\[b= \frac{(h-4)}{7}\]
Thank you :) Can you help me with two more? Then I'll be done for now. I'm just on a less time because I got up late and I have to work on another project soon. But first I have to get this math out of the way, my teacher makes us have perfectly correct answers
I'll try
wait 5min
ok :D thanks so much, ill be right back...
one leg of a right triangle is 6 millimeters shorter than longer leg, and hypotenuse is 6 millimeters longer than longer leg. Find lengths of sides of triangle.
so i need longer, shorter, and hypo :)
Longleg=x shorter leg= x-6 Hypo=x+6 (x+6)^2=(x-6)^2+x^2 x^2+12x+36=x^2-12x+36+x^2 x^2-24x=0 x(x-24)=0 x=0 or x=24
Yay thanks so much! One more question and I'm done...be right back :D
ok :)
oh which is longer etc?
It wants three answers
i've , mentioned everything can you tell me which is longer , shorter & hypotenuse?
hypo: 30 longer:24 short:19?
is short one 19?
24-6=18 :)
18? ok thanks :D Ill be back in a sec
Ok same problem but 1 mill instead of six :( My computer kicked me off and made me a new problem, I'm sorry
i didnt get you,what happend?
The problem reset
can you solve it with 1 instead of six used? mill wise :)
can you try out i'll help you
ok just a sec :)
I tried :( I just messed the whole thing up, the dumb x^2 confuses me
(x+1)^2=(x-1)^2+x^2 x^2+2x+1=x^2-2x+1+x^2 x^2-4x=0 x(x-4)=0 x=0 or x=4 longest=4 shortest =4-1=3 hypo=4+1=5
oh Diya thanks so much :)
Welcome =)
I have one more now ^_^ <3
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