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i^18
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i^18 = 1i^2 = -1
divide 18 by 4, take the integer remainder. you get 2 because \[18=4\times 16+2\] then write \[i^{18}=i^2=-1\]
i, -1, -i, 1 is the pattern it goes in. divisible by 4 = 1, divisible by 2 but not 4 = -1
i^4=1 i^18=i^(4(4)+2) i^4(4)xi^2 1x(-1) =-1
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