Question

(cos^3x-sin^3x)/(cosx-sinx) = 1+sinxcosx
Proving Trig Identity

Answer 1

\[(\cos^3x-\sin^3x)/(cosx-sinx) = 1+sinxcosx\]

Answer 2

multiply (cosx+sinx)/(cosx+sinx) to both sides

Answer 3

what will that do? :/

Answer 4

factoring the difference of two cubes might be a start

Answer 5

how would i factor them?

Answer 6

\[(a^3-b^3=(a-b)(a^2+ab+b^2)\]

Answer 7

\[a^3-b^3=(a-b)(a^2+ab+b^2)\]

Answer 8

oh like that. okay I'll try that thanks.

Answer 9

then cancel