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Trying to remember how to factor 1600X^2+880xy+121y^2
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(40x + 11y)^2
But how does that work out to the 880xy?
Well, you can see that 1600 = 40^2 and 121 = 11^2, so the first guess you should make is \[(40x +11y)(40x+11y)\] and see if it works. In this case, it does.
OK, looks like I was having a major mental block.
If you FOIL it, the 880 just pops right out.
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Right, I was thinking 40*11 was 44
oops
Thanks
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