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Mathematics 21 Online
OpenStudy (anonymous):

Solve (5x-4)^1/2=6

OpenStudy (anonymous):

Square both sides, solve for x

OpenStudy (anonymous):

\[(\sqrt{5x-4})^2=6^2\]

OpenStudy (anonymous):

My options are x=2, x=4, x=8, or none of the above

OpenStudy (anonymous):

What is the squart root of a number squared?

OpenStudy (anonymous):

idkk ?

OpenStudy (anonymous):

\[(\sqrt{x})^2=x\]

OpenStudy (anonymous):

Use that rule to solve for x in your equation

OpenStudy (anonymous):

There is no sqrt in this

OpenStudy (anonymous):

x^(1/2)=\[\sqrt{x}\]

OpenStudy (anonymous):

So none of the above

OpenStudy (anonymous):

I'm trying to explain.

OpenStudy (anonymous):

Do you understand that x^(1/2) is the sqrt of x?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

So there is a sqrt in this problem, then...

OpenStudy (anonymous):

look at my first response, can you figure that out?

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