Question

Solve x2 + 4x – 12 = 0 by completing the square. Show your work for full credit

Answer 1

factorise:

(x+6)(x-2)=0
therefore, either x+6=0 or x-2=0
x+6=0
x=-6

or

x-2=0
x=2

Answer 2

\[x^2 + 4x - 12 = 0\]

\[(x + 2)^2 -12 - 4 =0\]

\[(x + 2)^2 - 16 = 0\]

\[(x+2)^2 = 16\]

(x+2) = 4 OR (x+2)=-4

x = 2 OR x = -6

Answer 3

Yeah I goofed up and forgot to add the 4 to both sides

Answer 4

oh sorry, i didnt know what completing the square was :S