Question

3* Cube root of (x^2)- 10* Cube root of Radical X-9=o

Answer 1

And you're solving for x?

Answer 2

and i didnt mean radical x, haha, its already under a cube root

Answer 3

I'm afk for a while. Sorry. Someone will more likely be here to help soon.

Answer 4

let u=cubert(x)
3u^2-10u-8=0
(3u+2)(u-4)=0

so 3u+2=0
3*cubert(x)=-2
x=(-2/3)^3
x=-8/27

cubert(x)=4
x=4^3
x=64