Question

x^2y-2x+3y=6 differentiation to find tangent on a line help plzz

Answer 1

so you are trying to solve for dy/dx or y' ??

Answer 2

implicit

Answer 3

trying to find the tangent of the line but u have find d/dx first

Answer 4

\[\frac{dy}{dx} = \frac{2-2xy}{x^{2}+3}\]

Answer 5

y? i dnt understand hw u get that

Answer 6

by using implicit differentiation, you take derivative of each term but when you have a "y" the derivative is dy/dx

\[\rightarrow 2xy + x^{2}\frac{dy}{dx} -2 +3\frac{dy}{dx} = 0\]
then isolate and solve for dy/dx

Answer 7

ohhhh