Question

-48 ÷ (7 – 9)^3 – 2[1 – 5(2 – 6) + 3^2].

Answer 1

Hey there,

Just remember to "break up" the problem into smaller parts in order to solve it:

For instance:
-48 is one part..

(7-9)^3 is another that simply equals (-2)^3, or -8

So now you have:
-48/8..which is -6

Then go inside your []:
2-6 is -3, times 5 is -15

So now you have:
-6 - 2[1-(-15)+3^2]

1 minus -15 is 16.. 3^2 is 9,
and 16+9 is 25.
so now you have:
-6 - 2[25]

2 times 25 is 50, so now you have
-6 - 50
which is -56.

Answer 2

thanks i have been trying to solve this problem for 3 days now

Answer 3

You're very welcome! ..and remember, divide and conquer!