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a particle of mass 6kg is being pushed across a smooth horizontal plane by a force of 30N acting downwards at 20 degree to the vertical. find the acceleration of the particle and the force the particle exerts on the plane
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F=ma Fsin20=6a 30sin20=6a a=4.6m/s^2 (acceleration of particle)
Fcos20=force on plane=12N
how do you get Fcos 20 = force on plane = 12N?? i cant understand
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