Question

(2x2 – 23x + 63) ÷ (x – 7)

Answer 1

first lets try to factor 2x^2 - 23x + 63
we need two numbers with product = 63 and together with 2 give us - 23
these two numbers are 7 and 9.
so we get
(2x - 9)(x - 7)

so the division

= (2x - 9)( x-7)
----------
(x-7)

the (x-7) cancel out leaving 2x - 9

answer 2x - 9