A mechanical engineer bought 24 boxes of screws for P2200. There were three types of screws bough. Screw A cost P300 per box, screw B costs P150 per box and screw C costs P50 per box. How many boxes of each screw did he buy?

Question

anonymous · Answer

x= number of screw A boxes
y=number of screw B boxes
z=number of screw C boxes
x+y+z=24
300x+150y+50z=2200
Use substitution, elimination, or any other method you'd like and you'll get the solution XD

anonymous · Answer

A one Mathematica statement solution is attached.