to apply herbicide to a large field she must mix a solution of 67% herbicide with a solution of 46% herbicide to form 42 liters of a 55%solution.how much the 67%solution must they use ?
A.23L
B.18L
C.34L
D35L

Question

to apply herbicide to a large field she must mix a solution of 67% herbicide with a solution of 46% herbicide to form 42 liters of a 55%solution.how much the 67%solution must they use ?
A.23L
B.18L
C.34L
D35L

anonymous · Answer

B

anonymous · Answer

can you tell me the equation of how to solve it

anonymous · Answer

ok..

anonymous · Answer

attachment

anonymous · Answer

I used this web side to solve eq. http://math.cowpi.com/systemsolver/2x2.html

mertsj · Answer

x= liters of 67% solution
42-x= liters of 46% solution
.67x+.46(42-x)=.55(42)
Multiply both sides by 100 to get rid of decimal points:
67x+46(42-x)=55(42)
67x+1932-46x=2310
21x=378
x=18 liters of 67% solution
42-x=24 liters of 46% solution