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OpenStudy (anonymous):
Prove that (1-tan^2 A)/(1+tan^2 A) == cos2A
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OpenStudy (anonymous):
\[{1-\tan^2A \over 1+\tan^2A}={1-\tan^2A \over \sec^2A}={1 \over \sec^2A}-{\sin^2A \over \cos^2A}\cdot \cos^2A\] \[=\cos^2A-\sin^2A=\cos(2A).\]
OpenStudy (y2o2):
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